The reaction of one mole of 3-ethyl-3-methylp | vedclass

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Question

(D) The given compound is $3-$ethyl$-3-$methylpenta$-1, 4-$diene. Its structure is $CH_2=CH-C(CH_3)(C_2H_5)-CH=CH_2$. Ozonolysis followed by reductive

Vedclass · Accepted Answer

$2$ moles of $HCHO$ and $1$ mole of $OHC-C(CH_3)(C_2H_5)-CHO$

Vedclass · Answer

(D) The given compound is $3-$ethyl$-3-$methylpenta$-1, 4-$diene. Its structure is $CH_2=CH-C(CH_3)(C_2H_5)-CH=CH_2$. Ozonolysis followed by reductive workup $(Zn/H_2O)$ cleaves the double bonds and replaces them with carbonyl groups. Cleaving the two terminal double bonds $(CH_2=)$ results in the formation of $2$ moles of formaldehyde $(HCHO)$. The remaining central part of the molecule becomes a dicarbonyl compound: $OHC-C(CH_3)(C_2H_5)-CHO$. Thus,the products are $2$ moles of $HCHO$ and $1$ mole of $2-$ethyl$-2-$methylpropanedial.

The reaction of one mole of $3-$ethyl$-3-$methylpenta$-1, 4-$diene with $O_3$ and then with $Zn / H_2O$,gives

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