The resistance R = frac{V}{I},where V = 100 p | vedclass

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(B) Given: $V = 100 \pm 5 \, 	ext{V}$ and $I = 10 \pm 0.2 \, 	ext{A}$.Since $R = \frac{V}{I}$,the relative error in $R$ is given by $\frac{\Delta R}

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$7$

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(B) Given: $V = 100 \pm 5 \, 	ext{V}$ and $I = 10 \pm 0.2 \, 	ext{A}$.Since $R = \frac{V}{I}$,the relative error in $R$ is given by $\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}$.To find the percentage error,we multiply by $100$:$\left( \frac{\Delta R}{R} 	imes 100 ight)_{\max} = \left( \frac{\Delta V}{V} 	imes 100 ight) + \left( \frac{\Delta I}{I} 	imes 100 ight)$.Substituting the values:$= \left( \frac{5}{100} 	imes 100 ight) + \left( \frac{0.2}{10} 	imes 100 ight)$.$= 5\% + 2\% = 7\%$.Therefore,the total percentage error in $R$ is $7\%$.

The resistance $R = \frac{V}{I}$,where $V = 100 \pm 5 \, \text{volts}$ and $I = 10 \pm 0.2 \, \text{amperes}$. What is the total percentage error in $R$?

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