The resultant of two vectors $A$ and $B$ is perpendicular to the vector $A$ and its magnitude is equal to half the magnitude of vector $B$. The angle between $A$ and $B$ is ....... $^o$

Two vectors $A$ and $B$ have equal magnitude $x$. The angle between them is $60^{\circ}$. Match the following two columns:

Column $I$	Column $II$
$(A) |A+B|$	$(p) \frac{\sqrt{3}}{2} x^2$
$(B) |A-B|$	$(q) x$
$(C) A \cdot B$	$(r) \sqrt{3} x$
$(D) |A \times B|$	$(s) \frac{x^2}{2}$

The maximum and minimum magnitude of the resultant of two given vectors are $17$ units and $7$ units respectively. If these two vectors are at right angles to each other,the magnitude of their resultant is

If $\vec{A}=\hat{i}+\hat{j}+3 \hat{k}$,$\vec{B}=-\hat{i}+\hat{j}+4 \hat{k}$ and $\vec{C}=2 \hat{i}-2 \hat{j}-8 \hat{k}$,then the angle between the vectors $\vec{P}=\vec{A}+\vec{B}+\vec{C}$ and $\vec{Q}=(\vec{A} \times \vec{B})$ is (in degree) (in $^{\circ}$)

If $\theta$ is the angle between two vectors $\vec{A}$ and $\vec{B}$,then match the following two columns.

Column $I$	Column $II$
$(A)$ $\vec{A} \cdot \vec{B} = |\vec{A} \times \vec{B}|$	$(p)$ $\theta = 45^{\circ}$ or $135^{\circ}$
$(B)$ $\vec{A} \cdot \vec{B} = B^2$	$(q)$ $\theta = 0^{\circ}$
$(C)$ $|\vec{A} + \vec{B}| = |\vec{A} - \vec{B}|$	$(r)$ $\vec{A} = \vec{B}$
$(D)$ $|\vec{A} \times \vec{B}| = AB$	$(s)$ $\theta = 90^{\circ}$

If $\overrightarrow{A}=3 \hat{\imath}-2 \hat{\jmath}+\hat{k}$,$\overrightarrow{B}=\hat{\imath}-3 \hat{\jmath}+5 \hat{k}$ and $\overrightarrow{C}=2 \hat{\imath}+\hat{\jmath}-4 \hat{k}$ form a right-angled triangle,then which of the following is satisfied?