The roots of 4x^{2} + 2x + frac{1}{4} = 0 are | vedclass

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(C) Given quadratic equation is $4x^{2} + 2x + \frac{1}{4} = 0$.To simplify,multiply the entire equation by $4$:$16x^{2} + 8x + 1 = 0$.This is in the

Vedclass · Accepted Answer

$-\frac{1}{4}, -\frac{1}{4}$

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(C) Given quadratic equation is $4x^{2} + 2x + \frac{1}{4} = 0$.To simplify,multiply the entire equation by $4$:$16x^{2} + 8x + 1 = 0$.This is in the form of $(ax + b)^{2} = a^{2}x^{2} + 2abx + b^{2}$.Here,$(4x)^{2} + 2(4x)(1) + (1)^{2} = 0$.This simplifies to $(4x + 1)^{2} = 0$.Therefore,$4x + 1 = 0$,which gives $4x = -1$.So,$x = -\frac{1}{4}$.The roots are $-\frac{1}{4}, -\frac{1}{4}$.

The roots of $4x^{2} + 2x + \frac{1}{4} = 0$ are $\ldots \ldots \ldots \ldots.$

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