The roots of the equation 3 a^{2} x^{2}-a b x | vedclass

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Question

(A) The given quadratic equation is $3 a^{2} x^{2}-a b x-2 b^{2}=0$.We can factorize the middle term $-abx$ as $-3abx + 2abx$:$3 a^{2} x^{2}-3 a b x+2

Vedclass · Accepted Answer

$b/a, -2b/3a$

Vedclass · Answer

(A) The given quadratic equation is $3 a^{2} x^{2}-a b x-2 b^{2}=0$.We can factorize the middle term $-abx$ as $-3abx + 2abx$:$3 a^{2} x^{2}-3 a b x+2 a b x-2 b^{2}=0$Taking common terms from the groups:$3 a x(a x-b)+2 b(a x-b)=0$$(a x-b)(3 a x+2 b)=0$Setting each factor to zero:$a x-b=0 \Rightarrow x=b/a$$3 a x+2 b=0 \Rightarrow x=-2b/3a$Thus,the roots are $b/a$ and $-2b/3a$.

The roots of the equation $3 a^{2} x^{2}-a b x-2 b^{2}=0$ are

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