The set of quantum numbers for the 19^{th} el | vedclass

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(A) The atomic number of chromium $(Cr)$ is $24$.Its electronic configuration is $[Ar] 3d^5 4s^1$.The order of filling electrons according to the Aufb

Vedclass · Accepted Answer

$n = 4, l = 0, m = 0, s = +1/2 	ext{ or } -1/2$

Vedclass · Answer

(A) The atomic number of chromium $(Cr)$ is $24$.Its electronic configuration is $[Ar] 3d^5 4s^1$.The order of filling electrons according to the Aufbau principle is $1s, 2s, 2p, 3s, 3p, 4s, 3d$.The first $18$ electrons fill the argon core $(1s^2 2s^2 2p^6 3s^2 3p^6)$.The $19^{th}$ electron enters the $4s$ orbital.For the $4s$ orbital,the principal quantum number $n = 4$ and the azimuthal quantum number $l = 0$.Since $l = 0$,the magnetic quantum number $m = 0$.The spin quantum number $s$ can be $+1/2$ or $-1/2$.

The set of quantum numbers for the $19^{th}$ electron in chromium $(Cr)$ is:

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