The shaded part of the given figure indicates | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The shaded region is bounded by the lines $x=0$ ($Y$-axis),$y=0$ ($X$-axis),$x=5$,$y=3$,and the line passing through $(0,0)$ and $(3,3)$.$2$.

Vedclass · Accepted Answer

$x, y \geq 0 ; x-y \geq 0 ; x \leq 5 ; y \leq 3$

Vedclass · Answer

(A) $1$. The shaded region is bounded by the lines $x=0$ ($Y$-axis),$y=0$ ($X$-axis),$x=5$,$y=3$,and the line passing through $(0,0)$ and $(3,3)$.$2$. The line passing through $(0,0)$ and $(3,3)$ has the equation $y=x$,which can be written as $x-y=0$. Since the shaded region lies below this line,the constraint is $x-y \geq 0$.$3$. The vertical line $x=5$ bounds the region on the right,so $x \leq 5$.$4$. The horizontal line $y=3$ bounds the region on the top,so $y \leq 3$.$5$. Since the region is in the first quadrant,$x \geq 0$ and $y \geq 0$.$6$. Combining these,the constraints are $x, y \geq 0, x-y \geq 0, x \leq 5, y \leq 3$.

The shaded part of the given figure indicates the feasible region. Then the constraints are

Similar Questions

The difference between the maximum value and minimum value of the objective function $z = 3x + 5y$ of a linear programming problem subject to constraints $5x + 10y \leq 50$, $x + y \geq 1$, $y \leq 4$, $x \geq 0$, $y \geq 0$ is $3\lambda$. Then the value of $\lambda$ is

The minimum value of $t = 7x + 3y$ subject to constraints $x + y < 5$,$x + y < 10$,$x > 0$,$y > 0$ is . . . . . .

The difference between the maximum value and the minimum value of the objective function $z = 3x + y$ subject to the constraints $2x + 3y \leq 6$, $x + y \geq 1$, $x \geq 0$, $y \geq 0$ is....

The maximum value of $Z = 5x + 2y$,subject to the constraints $2x - y \geq 2$,$x + 2y \leq 8$,and $x, y \geq 0$,is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module