The shape of [Cu(NH_3)_4]^{2+} is square plan | vedclass

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(B) The electronic configuration of $Cu$ $(Z=29)$ is $[Ar] 3d^{10} 4s^1$. For $Cu^{2+}$,the configuration is $[Ar] 3d^9$. In the $[Cu(NH_3)_4]^{2+}$ c

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$dsp^2$ hybridised

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(B) The electronic configuration of $Cu$ $(Z=29)$ is $[Ar] 3d^{10} 4s^1$. For $Cu^{2+}$,the configuration is $[Ar] 3d^9$. In the $[Cu(NH_3)_4]^{2+}$ complex,the $Cu^{2+}$ ion undergoes $dsp^2$ hybridisation to form a square planar geometry. One of the $3d$ electrons is promoted to the $4p$ orbital to allow for the $dsp^2$ hybridisation,which involves one $3d$,one $4s$,and two $4p$ orbitals.

The shape of $[Cu(NH_3)_4]^{2+}$ is square planar. The $Cu^{2+}$ ion in this complex is:

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