The solution is $2 \ L$ of $0.02 \ M \ NaOH$. The solubility product of $Zn(OH)_2$ is $4.5 \times 10^{-17}$. Then how many grams of $Zn(OH)_2$ is maximum soluble in the given $NaOH$ solution?

  • A
    $2.228 \times 10^{-11} \ g$
  • B
    $4.456 \times 10^{-11} \ g$
  • C
    $1.114 \times 10^{-11} \ g$
  • D
    $8.912 \times 10^{-11} \ g$

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