The statements p, q and r have truth values T | vedclass

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(B) Given truth values: $p = T, q = F, r = F$.Step $1$: Evaluate the statement $S = [\sim (p \wedge \sim q) \vee (q \vee \sim r)]$.$\sim q = \sim F =

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(B) Given truth values: $p = T, q = F, r = F$.Step $1$: Evaluate the statement $S = [\sim (p \wedge \sim q) \vee (q \vee \sim r)]$.$\sim q = \sim F = T$.$(p \wedge \sim q) = (T \wedge T) = T$.$\sim (p \wedge \sim q) = \sim T = F$.$(q \vee \sim r) = (F \vee \sim F) = (F \vee T) = T$.$S = (F \vee T) = T$.Step $2$: Find the dual statement $S^*$. To find the dual, replace $\wedge$ with $\vee$, $\vee$ with $\wedge$, $T$ with $F$, and $F$ with $T$.$S^* = [\sim (p \vee \sim q) \wedge (q \wedge \sim r)]$.Step $3$: Evaluate $S^*$.$(p \vee \sim q) = (T \vee T) = T$.$\sim (p \vee \sim q) = \sim T = F$.$(q \wedge \sim r) = (F \wedge T) = F$.$S^* = (F \wedge F) = F$.Thus, the truth values are $T$ and $F$.

The statements $p, q$ and $r$ have truth values $T, F$ and $F$ respectively. The truth values of a logical statement $[\sim (p \wedge \sim q) \vee (q \vee \sim r)]$ and its dual are, respectively.....

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