$\frac{1}{2} + \frac{1}{3} \cdot \frac{1}{2^3} + \frac{1}{5} \cdot \frac{1}{2^5} + \dots \infty$ का योग क्या है?

  • A
    $\log_e \sqrt{\frac{3}{2}}$
  • B
    $\log_e \sqrt{3}$
  • C
    $\log_e \sqrt{\frac{1}{2}}$
  • D
    $\log_e 3$

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Similar Questions

$1 + \frac{2}{3} - \frac{2}{4} + \frac{2}{5} - \dots \infty = $

$(0.5) - \frac{(0.5)^2}{2} + \frac{(0.5)^3}{3} - \frac{(0.5)^4}{4} + \dots$

मान लीजिए कि $\alpha$ और $\beta$ समीकरण $5x^2 - 3x - 1 = 0$ के मूल हैं। तो व्यंजक $\left[ (\alpha + \beta)x - \left( \frac{\alpha^2 + \beta^2}{2} \right)x^2 + \left( \frac{\alpha^3 + \beta^3}{3} \right)x^3 - \dots \right]$ किसके बराबर है?

$\frac{1}{5} + \frac{1}{2} \cdot \frac{1}{5^2} + \frac{1}{3} \cdot \frac{1}{5^3} + \dots \infty = $

यदि $-\frac{\pi}{2} < \theta < \frac{\pi}{2}$ है,तो $\log \left(\tan \left(\frac{\pi}{4}+\frac{\theta}{2}\right)\right)=$

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