The sum of focal radii of the curve 9x^{2} + | vedclass

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(B) The given equation of the curve is $9x^{2} + 25y^{2} = 225$. Dividing both sides by $225$,we get $\frac{9x^{2}}{225} + \frac{25y^{2}}{225} = 1$,wh

Vedclass · Accepted Answer

$10$

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(B) The given equation of the curve is $9x^{2} + 25y^{2} = 225$. Dividing both sides by $225$,we get $\frac{9x^{2}}{225} + \frac{25y^{2}}{225} = 1$,which simplifies to $\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1$. This is the equation of an ellipse of the form $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$,where $a^{2} = 25$ and $b^{2} = 9$. Thus,$a = 5$ and $b = 3$. For an ellipse,the sum of the focal radii of any point on the curve is equal to the length of the major axis,which is $2a$. Therefore,the sum of focal radii $= 2 	imes 5 = 10$.

The sum of focal radii of the curve $9x^{2} + 25y^{2} = 225$ is

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