The sum of squares of two numbers is $90$ and the square of their difference is $46$. The product of the two numbers is

In a two-digit number,the digit in the unit's place is $1$ more than twice the digit in the ten's place. If the digits in the unit's place and the ten's place are interchanged,the difference between the new number and the original number is $1$ less than the original number. What is the original number?

If $m$ and $n$ are positive integers and $(m-n)$ is an even number,then $(m^{2}-n^{2})$ will be always divisible by

$525 \times 24 \div 8 + 25 = (?)^2$

The least positive integer that should be subtracted from $3011 \times 3012$ so that the difference is a perfect square,is

$69.69 - 51.54 + 73.64 = ? + 32.42$