The value of 1-frac{a}{1-frac{1}{1+frac{a}{1- | vedclass

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(B) To simplify the expression $1-\frac{a}{1-\frac{1}{1+\frac{a}{1-a}}}$,we start from the innermost fraction:First,simplify the denominator $1+\frac{

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$0$

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(B) To simplify the expression $1-\frac{a}{1-\frac{1}{1+\frac{a}{1-a}}}$,we start from the innermost fraction:First,simplify the denominator $1+\frac{a}{1-a}$:$1+\frac{a}{1-a} = \frac{1-a+a}{1-a} = \frac{1}{1-a}$Next,substitute this back into the expression:$1-\frac{a}{1-\frac{1}{\frac{1}{1-a}}} = 1-\frac{a}{1-(1-a)}$Now,simplify the denominator $1-(1-a)$:$1-1+a = a$Finally,substitute this back:$1-\frac{a}{a} = 1-1 = 0$Thus,the correct option is $B$.

The value of $1-\frac{a}{1-\frac{1}{1+\frac{a}{1-a}}}$ is

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