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(B) The Trapezoidal rule for numerical integration is given by:$	ext{Distance} = \int_{0}^{10} v(t) \ dt \approx \frac{h}{2} [v_0 + 2(v_1 + v_2 + v_3

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$226$

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(B) The Trapezoidal rule for numerical integration is given by:$	ext{Distance} = \int_{0}^{10} v(t) \ dt \approx \frac{h}{2} [v_0 + 2(v_1 + v_2 + v_3 + v_4) + v_5]$Here,the interval width $h = 2 \ s$.The values are $v_0 = 0, v_1 = 12, v_2 = 16, v_3 = 20, v_4 = 35, v_5 = 60$.Substituting these values into the formula:$	ext{Distance} = \frac{2}{2} [0 + 2(12 + 16 + 20 + 35) + 60]$$	ext{Distance} = 1 	imes [0 + 2(83) + 60]$$	ext{Distance} = 166 + 60 = 226 \ m$.

$t$ (in second)	$0$	$2$	$4$	$6$	$8$	$10$
$v$ (in m/s)	$0$	$12$	$16$	$20$	$35$	$60$

The velocity of a particle which starts from rest is given by the following table. The total distance travelled (in metre) by the particle in $10 \ s$,using the Trapezoidal rule is given by:
$t$ (in second) $0$ $2$ $4$ $6$ $8$ $10$
$v$ (in m/s) $0$ $12$ $16$ $20$ $35$ $60$

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The velocity of a particle which starts from rest is given by the following table. The total distance travelled (in metre) by the particle in $10 \ s$,using the Trapezoidal rule is given by:$t$ (in second)$0$$2$$4$$6$$8$$10$$v$ (in m/s)$0$$12$$16$$20$$35$$60$