The vertex of the right angle of a right-angled triangle lies on the straight line $2x + y - 10 = 0$. If the two other vertices are at points $(2, -3)$ and $(4, 1)$,then the area of the triangle in sq. units is:

  • A
    $\sqrt{10}$
  • B
    $3$
  • C
    $\frac{33}{5}$
  • D
    $11$

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