The Vividh Bharati station of All India Radio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The wavelength,$\lambda$,is calculated using the formula $\lambda = c / 
u$,where $c$ is the speed of light $(3.00 	imes 10^{8} \, m \, s^{-1})$

Vedclass · Accepted Answer

$219.3 \, m$,Radio waves

Vedclass · Answer

(A) The wavelength,$\lambda$,is calculated using the formula $\lambda = c / 
u$,where $c$ is the speed of light $(3.00 	imes 10^{8} \, m \, s^{-1})$ and $
u$ is the frequency.Given frequency $
u = 1368 \, kHz = 1368 	imes 10^{3} \, s^{-1}$.Substituting the values:$\lambda = \frac{3.00 	imes 10^{8} \, m \, s^{-1}}{1368 	imes 10^{3} \, s^{-1}}$$\lambda = 219.3 \, m$Since the wavelength is in the range of meters,this radiation belongs to the radio wave region of the electromagnetic spectrum.

The Vividh Bharati station of All India Radio,Delhi,broadcasts on a frequency of $1368 \, kHz$ (kilo hertz). Calculate the wavelength of the electromagnetic radiation emitted by the transmitter. Which part of the electromagnetic spectrum does it belong to?

Similar Questions

The frequency of yellow light having wavelength $600 \ nm$ is

$750$ waves of an energy radiation pass in one minute from a point. What will be the wavelength of the radiation? (Assume the speed of radiation is $3 \times 10^8 \ m/s$)

If the energies of two photons are in the ratio of $3:2$,their wavelengths will be in the ratio of

Calculate the wavelength,frequency and wave number of a light wave whose period is $2.0 \times 10^{-10} \,s$.

Which of the following series correctly represents the energy of the radiation?

Vedclass Test Series

Exam Paper Generator

Online Exam Module