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(C) Let the resistance of each resistor be $R$. The resistors $B$ and $C$ are connected in parallel,so their equivalent resistance is $R_p = \frac{R \

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In $A$

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(C) Let the resistance of each resistor be $R$. The resistors $B$ and $C$ are connected in parallel,so their equivalent resistance is $R_p = \frac{R 	imes R}{R + R} = \frac{R}{2}$.This combination is in series with resistor $A$. The total current $I$ flows through $A$,while the current splits equally between $B$ and $C$ because they are identical.The heat produced in a resistor is given by $H = I^2 R t$.For resistor $A$,$H_A = I^2 R t$.For resistors $B$ and $C$,the current through each is $I/2$. Thus,$H_B = H_C = (I/2)^2 R t = \frac{I^2 R t}{4} = \frac{H_A}{4}$.Comparing these,$H_A > H_B = H_C$. Therefore,the heat produced is maximum in resistor $A$.

Three identical resistances $A$,$B$,and $C$ are connected as shown in the given figure. The heat produced will be maximum in:

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