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(D) When a charged particle moves with velocity $v$ perpendicular to a uniform magnetic field $B$ (i.e.,$	heta = 90^{\circ}$), it experiences a magne

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momentum of the particle

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(D) When a charged particle moves with velocity $v$ perpendicular to a uniform magnetic field $B$ (i.e.,$	heta = 90^{\circ}$), it experiences a magnetic Lorentz force $F = qvB$.This force acts perpendicular to the velocity, providing the necessary centripetal force for circular motion:$qvB = \frac{mv^2}{r}$Solving for the radius $r$:$r = \frac{mv}{qB}$Since the momentum of the particle is $p = mv$, we can write:$r = \frac{p}{qB}$From this expression, it is clear that the radius $r$ is directly proportional to the momentum $p$ of the particle.Therefore, option $(D)$ is correct.

To which of the following quantities, the radius of the circular path of a charged particle moving at right angles to a uniform magnetic field is directly proportional?

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