Two balanced dice are rolled. Find the probab | vedclass

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(D) When two balanced dice are rolled,the total number of possible outcomes is $6 	imes 6 = 36$.The possible sums of the numbers on the two dice rang

Vedclass · Accepted Answer

$1/6$

Vedclass · Answer

(D) When two balanced dice are rolled,the total number of possible outcomes is $6 	imes 6 = 36$.The possible sums of the numbers on the two dice range from $2$ to $12$.The sums that are multiples of $6$ are $6$ and $12$.For a sum of $6$,the possible outcomes are $(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)$. There are $5$ such outcomes.For a sum of $12$,the only possible outcome is $(6, 6)$. There is $1$ such outcome.Total favorable outcomes = $5 + 1 = 6$.Probability = $\frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{6}{36} = \frac{1}{6}$.

Two balanced dice are rolled. Find the probability that the sum of numbers on two dice is a multiple of $6$.

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