Two blocks (A) of 2,kg and (B) of 5,kg rest o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For block $A$ to move with block $B$ without any relative motion,the maximum acceleration $a_{max}$ of the system is provided by the friction forc

Vedclass · Accepted Answer

$42\,N$

Vedclass · Answer

(A) For block $A$ to move with block $B$ without any relative motion,the maximum acceleration $a_{max}$ of the system is provided by the friction force between $A$ and $B$.The limiting friction force on block $A$ is $f_{max} = \mu N_A = \mu m_A g$.Using Newton's second law for block $A$,$f_{max} = m_A a_{max}$.Therefore,$m_A a_{max} = \mu m_A g$,which gives $a_{max} = \mu g$.Given $\mu = 0.60$ and $g = 10\,m/s^2$,we have $a_{max} = 0.60 	imes 10 = 6\,m/s^2$.Now,considering both blocks $A$ and $B$ as a single system of mass $(m_A + m_B)$,the maximum force $F_{max}$ that can be applied to $B$ is $F_{max} = (m_A + m_B) a_{max}$.Substituting the values,$F_{max} = (2 + 5) 	imes 6 = 7 	imes 6 = 42\,N$.

Similar Questions

If force $F$ is increasing with time and at $t = 0, F = 0$,where will slipping first start?

Imagine a situation in which the horizontal surface of block $M_0$ is smooth and its vertical surface is rough with a coefficient of friction $\mu$. Identify the correct statement$(s)$.

The frictional force acting on the $1 \,kg$ block is .................. $N$.

If the acceleration of block $A$ is $2 \, m/s^2$,which is provided by the frictional force from block $B$,then the magnitude of the frictional force applied by block $B$ on block $A$ is ......... $N$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module