(B) In the first cask ($48$ $litres$): Wine $= \frac{13}{20} \times 48 = 31.2$ $litres$,Water $= \frac{7}{20} \times 48 = 16.8$ $litres$.In the second

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) In the first cask ($48$ $litres$): Wine $= \frac{13}{20} \times 48 = 31.2$ $litres$,Water $= \frac{7}{20} \times 48 = 16.8$ $litres$.In the second cask ($42$ $litres$): Wine $= \frac{18}{35} \times 42 = 21.6$ $litres$,Water $= \frac{17}{35} \times 42 = 20.4$ $litres$.Total wine $= 31.2 + 21.6 = 52.8$ $litres$.Total water $= 16.8 + 20.4 = 37.2$ $litres$.After adding $20$ $litres$ of water,total water $= 37.2 + 20 = 57.2$ $litres$.The ratio of wine to water $= 52.8 : 57.2 = 528 : 572$.Dividing both by $44$,we get $12 : 13$.

Competitive Quantitative Aptitude Mixture and Alligation Mixture and Alligation

Difficult

Two casks of $48$ $litres$ and $42$ $litres$ are filled with mixtures of wine and water,the proportions in the two casks being respectively $13:7$ and $18:17$. If the contents of the two casks are mixed,and $20$ $litres$ of water is added to the whole,what will be the proportion of wine to water in the resultant mixture?

A
$13:12$
B
$12:13$
C
$21:31$
D
$31:21$

Explore More

Browse All

Question Bank

All Subjects

Competitive Questions

Competitive

Quantitative Aptitude Questions

Chapter

Mixture and Alligation

Subtopic

Mixture and Alligation

The acid and water in two vessels $A$ and $B$ are in the ratio $4:3$ and $2:3$. In what ratio should the liquids in both the vessels be mixed to obtain a new mixture in vessel $C$ containing half acid and half water?

Difficult

View Solution

Gold is $21$ times as heavy as water and copper is $11$ times as heavy as water. In what ratio should these metals be mixed so that the mixture may be $17$ times as heavy as water?

Medium

View Solution

Two types of alloys contain gold and silver in the ratio of $7: 22$ and $21: 37.$ In what ratio should these alloys be mixed,so as to have a new alloy in which gold and silver would exist in the ratio $25: 62?$

Medium

View Solution

The ratio of milk and water in mixtures of four containers are $5:3, 2:1, 3:2$ and $7:4$ respectively. In which container is the quantity of milk,relative to water,minimum?

Easy

View Solution

$A$ person travels $285 \text{ km}$ in $6 \text{ hours}$ in two stages. In the first part of the journey,he travels by bus at a speed of $40 \text{ km/h}$. In the second part of the journey,he travels by train at a speed of $55 \text{ km/h}$. How much distance did he travel by train? (in $\text{km}$)

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

The acid and water in two vessels $A$ and $B$ are in the ratio $4:3$ and $2:3$. In what ratio should the liquids in both the vessels be mixed to obtain a new mixture in vessel $C$ containing half acid and half water?

Gold is $21$ times as heavy as water and copper is $11$ times as heavy as water. In what ratio should these metals be mixed so that the mixture may be $17$ times as heavy as water?

Two types of alloys contain gold and silver in the ratio of $7: 22$ and $21: 37.$ In what ratio should these alloys be mixed,so as to have a new alloy in which gold and silver would exist in the ratio $25: 62?$

The ratio of milk and water in mixtures of four containers are $5:3, 2:1, 3:2$ and $7:4$ respectively. In which container is the quantity of milk,relative to water,minimum?

Vedclass Test Series

Exam Paper Generator

Online Exam Module