Two identical point charges are placed at a s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $q$ be the magnitude of the two identical point charges placed at $x=0$ and $x=l$.The electric field at a point $P$ at a distance $x$ from the

Vedclass · Accepted Answer

Vedclass · Answer

(D) Let $q$ be the magnitude of the two identical point charges placed at $x=0$ and $x=l$.The electric field at a point $P$ at a distance $x$ from the first charge (at $x=0$) is the vector sum of the fields due to both charges.The field due to the first charge is $E_1 = \frac{kq}{x^2}$ (directed away from the charge).The field due to the second charge (at $x=l$) is $E_2 = \frac{kq}{(l-x)^2}$ (directed towards the first charge).Taking the direction away from the first charge as positive,the net electric field $E$ at point $P$ is:$E = E_1 - E_2 = kq \left[ \frac{1}{x^2} - \frac{1}{(l-x)^2} ight]$As $x 	o 0$,$E 	o +\infty$.As $x 	o l$,$E 	o -\infty$.At the midpoint $x = l/2$,$E = kq \left[ \frac{1}{(l/2)^2} - \frac{1}{(l/2)^2} ight] = 0$.The curve that shows $E$ starting from positive infinity,passing through zero at $x = l/2$,and approaching negative infinity as $x$ approaches $l$ is represented by option $(D)$.

Similar Questions

$A$ charge $Q$ is uniformly distributed over the surface of a thin spherical shell of radius $R$. Which of the following graphs most closely represents the electric field $E(r)$ produced by the shell in the range $0 \leq r < \infty$,where $r$ is the distance from the center of the shell?

$A$ charge $Q$ is placed at each of the opposite corners of a square. $A$ charge $q$ is placed at each of the other two corners. If the net electrical force on $Q$ is zero,then $\frac{Q}{q} = $ . . . . . .

Three negative charges of equal magnitude $q$ are placed at the vertices of an equilateral triangle. The electric field lines will look like:

Six point charges are placed at the vertices of a regular hexagon of side $a$ as shown. If $E$ represents the electric field and $V$ represents the electric potential at the center $O$,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module