Two liquids of densities $d_1$ and $d_2$ are flowing in identical capillary tubes under the same pressure difference. If $t_1$ and $t_2$ are the times taken for the flow of equal quantities (mass) of liquids,then the ratio of the coefficient of viscosity of the liquids must be:

  • A
    $\frac{d_1 t_1}{d_2 t_2}$
  • B
    $\frac{t_1}{t_2}$
  • C
    $\frac{d_2 t_2}{d_1 t_1}$
  • D
    $\sqrt{\frac{d_1 t_1}{d_2 t_2}}$

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