Two capillary tubes of same length each of $50 \ cm$ but of different radii $4 \ mm$ and $2 \ mm$ are connected in series. When water flows,the pressure difference between the ends of the arrangement is $P$. Then the pressure difference between the ends of the first tube is

  • A
    $\frac{P}{2}$
  • B
    $\frac{P}{17}$
  • C
    $\frac{P}{4}$
  • D
    $\frac{P}{8}$

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