Two teams $A$ and $B$ have the same mean and their coefficients of variation are $4$ and $2$,respectively. If $\sigma_A$ and $\sigma_B$ are the standard deviations of teams $A$ and $B$ respectively,then the relation between them is

  • A
    $\sigma_A = \sigma_B$
  • B
    $\sigma_B = 2 \sigma_A$
  • C
    $\sigma_A = 2 \sigma_B$
  • D
    $\sigma_B = 4 \sigma_A$

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Similar Questions

The mean and variance of a series of $5$ observations are $8$ and $24$ respectively. The mean and variance of another series of $3$ observations are $8$ and $24$ respectively. What is the variance of their combined series?

Difficult
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The variance of the following frequency distribution is:
Classes$0-10$$10-20$$20-30$$30-40$$40-50$$50-60$
Frequency$11$$29$$18$$4$$5$$3$

Let $\mu$ be the mean and $\sigma$ be the standard deviation of the distribution:
$X_i$$0$$1$$2$$3$$4$$5$
$f_i$$k+2$$2k$$k^2-1$$k^2-1$$k^2-1$$k-3$
where $\sum f_i=62$. If $[x]$ denotes the greatest integer $\leq x$,then $[\mu^2+\sigma^2]$ is equal to:

If $A$ and $B$ are the variances of the first $n$ even numbers and the first $n$ odd numbers respectively,then:

Find the standard deviation for the following data:
${x_i}$ $3$ $8$ $13$ $18$ $23$
${f_i}$ $7$ $10$ $15$ $10$ $6$

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