Two waves are superimposed whose ratio of int | vedclass

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(B) Given,the ratio of intensities of two waves is $\frac{I_1}{I_2} = \frac{9}{1}$.Since intensity $I \propto a^2$,where $a$ is the amplitude,we have:

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$4: 1$

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(B) Given,the ratio of intensities of two waves is $\frac{I_1}{I_2} = \frac{9}{1}$.Since intensity $I \propto a^2$,where $a$ is the amplitude,we have:$\frac{I_1}{I_2} = \left(\frac{a_1}{a_2}\right)^2 = \frac{9}{1}$Taking the square root on both sides:$\frac{a_1}{a_2} = \frac{3}{1} \Rightarrow a_1 = 3a_2$.The ratio of maximum to minimum intensity is given by:$\frac{I_{\max}}{I_{\min}} = \frac{(a_1 + a_2)^2}{(a_1 - a_2)^2}$Substituting $a_1 = 3a_2$:$\frac{I_{\max}}{I_{\min}} = \frac{(3a_2 + a_2)^2}{(3a_2 - a_2)^2} = \frac{(4a_2)^2}{(2a_2)^2} = \frac{16a_2^2}{4a_2^2} = \frac{4}{1}$.

Two waves are superimposed whose ratio of intensities is $9: 1$. The ratio of maximum and minimum intensity is

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