Two waves with same amplitude and frequency superpose at a point. The ratio of resultant intensities when they arrive in phase to that when they arrive $90^{\circ}$ out of phase is $\left[\cos \frac{\pi}{2}=0\right]$

Two waves of amplitudes $A_0$ and $x A_0$ pass through a region. If $x > 1$,the difference between the maximum and minimum resultant amplitude possible is

Obtain the resultant wave of more than two wave functions by representing the superposition principle mathematically.

Two waves $y_1 = A_1 \sin(\omega t - \beta_1)$ and $y_2 = A_2 \sin(\omega t - \beta_2)$ superimpose to form a resultant wave whose amplitude is:

Three coherent waves of equal frequencies having amplitudes $10 \, \mu m$,$4 \, \mu m$,and $7 \, \mu m$ respectively,arrive at a given point with successive phase differences of $\pi / 2$. The amplitude of the resulting wave in $\mu m$ is given by

When two sound waves having amplitude $3$ and $5$ units are superimposed,then the ratio of maximum to minimum intensity of the wave produced is: