Under steady state condition, the potential d | vedclass

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(B) In steady state, the capacitor acts as an open circuit, meaning no current flows through the branch containing the capacitor.Therefore, the curren

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(B) In steady state, the capacitor acts as an open circuit, meaning no current flows through the branch containing the capacitor.Therefore, the current in the circuit flows only through the $2\Omega$ and $6\Omega$ resistors which are in series with the $2	ext{V}$ battery.The total resistance of the circuit is $R = 2\Omega + 6\Omega = 8\Omega$.The current in the circuit is $I = V / R = 2	ext{V} / 8\Omega = 0.25	ext{A}$.The potential difference across the $6\Omega$ resistor is $V_6 = I 	imes 6\Omega = 0.25	ext{A} 	imes 6\Omega = 1.5	ext{V}$.Since the capacitor branch is in parallel with the $6\Omega$ resistor, the potential difference across the capacitor is equal to the potential difference across the $6\Omega$ resistor.Thus, the potential difference across the capacitor is $1.5	ext{V}$.

Under steady state condition, the potential difference across the capacitor in the circuit is . . . . . . $V$.

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