The vertex of the parabola $9x^2 - 6x + 36y + 9 = 0$ is

  • A
    $(1/3, -2/9)$
  • B
    $(-1/3, -1/2)$
  • C
    $(-1/3, 1/2)$
  • D
    $(1/3, 1/2)$

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Let $A$ and $B$ be two distinct points on the parabola $y^2 = 4x$. If the axis of the parabola touches a circle of radius $r$ having $AB$ as its diameter,then the slope of the line joining $A$ and $B$ can be

Match the items of List-$I$ with those of List-$II$. Then,which of the following is correct?
List-$I$List-$II$
$A$. Equation of the tangent drawn at $(2, \sqrt{8})$ on the curve $y^2 = 4x$ is$(i) -36$
$B$. Equation of the normal to the curve $y^2 = 16x$,that makes an angle of $45^{\circ}$ with its axis is$(ii) 4$
$C$. The chord joining the points $(x_1, y_1)$ and $(x_2, y_2)$ on the curve $y^2 = 12x$ is a focal chord if $y_1 y_2 =$$(iii) 8$
$D$. $A$ value of $k$ for which $x - 3 = 0$ is the directrix of the curve $y^2 - kx + 16 = 0$ is$(iv) x - \sqrt{2}y + 2 = 0$
$(v) x + y - 12 = 0$
$(vi) x - y - 12 = 0$

If the focus of a parabola is $(0,-3)$ and its directrix is $y=3$,then its equation is

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