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(B) In the given circuit,the two capacitors of $2 \, \mu F$ each are connected in series. Their equivalent capacitance $C_s$ is given by:$\frac{1}{C_s

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$2$

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(B) In the given circuit,the two capacitors of $2 \, \mu F$ each are connected in series. Their equivalent capacitance $C_s$ is given by:$\frac{1}{C_s} = \frac{1}{2} + \frac{1}{2} = 1 \implies C_s = 1 \, \mu F$.This equivalent capacitor is now in parallel with the $1 \, \mu F$ capacitor connected between $A$ and $B$.The total effective capacitance $C_{AB}$ is:$C_{AB} = C_s + 1 \, \mu F = 1 \, \mu F + 1 \, \mu F = 2 \, \mu F$.Thus,the correct option is $B$.

What is the effective capacitance between $A$ and $B$ in the following figure in $\mu F$?

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