What is the temperature at which the kinetic | vedclass

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(C) The kinetic energy $(KE)$ of an ideal gas is given by the formula $KE = nRT$, where $n$ is the number of moles, $R$ is the gas constant, and $T$ i

Vedclass · Accepted Answer

$533$

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(C) The kinetic energy $(KE)$ of an ideal gas is given by the formula $KE = nRT$, where $n$ is the number of moles, $R$ is the gas constant, and $T$ is the temperature in Kelvin.Given:For helium: $n_{He} = 0.3 	ext{ mol}$For argon: $n_{Ar} = 0.4 	ext{ mol}$, $T_{Ar} = 400 	ext{ K}$According to the problem, $KE_{He} = KE_{Ar}$.Substituting the values:$0.3 	imes R 	imes T = 0.4 	imes R 	imes 400$Dividing both sides by $R$:$0.3 	imes T = 160$$T = \frac{160}{0.3} = 533.33 	ext{ K} \approx 533 	ext{ K}$.

What is the temperature at which the kinetic energy of $0.3 \text{ moles}$ of helium is equal to the kinetic energy of $0.4 \text{ moles}$ of argon at $400 \text{ K}$ (in $\text{ K}$)?

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