What is the value of shunt resistance required to convert a galvanometer of resistance $ 100 \Omega $ into an ammeter of range $ 1 \text{ A} $? Given: Full scale deflection of the galvanometer is $ 5 \text{ mA} $.

  • A
    $ \frac{5}{9.95} \Omega $
  • B
    $ \frac{9.95}{5} \Omega $
  • C
    $ 0.5 \Omega $
  • D
    $ 0.05 \Omega $

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Similar Questions

In an experiment to find the resistance of a galvanometer by the half-deflection method, a $5 V$ battery and a high resistance of $4.9 k\Omega$ are connected in the circuit. In the absence of any shunt resistance, the galvanometer reads $20$ divisions when current flows in the circuit. To reduce the deflection by half, the value of the shunt resistance used is $98 \Omega$. The figure of merit of the galvanometer is given as $..... \mu A / \text{division}$.

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Define the function of the small cylinder in the construction of a galvanometer.

An ideal ammeter and an ideal voltmeter have resistances of . . . . . . $\Omega$ and . . . . . . $\Omega$ respectively.

An ammeter has a range of $1 \, A$ without a shunt. The range can be varied by using different shunt resistances. The graph between shunt resistance $(S)$ and range $(I)$ will have the nature of which curve shown in the figure?

An ammeter of resistance $R$ gives a full-scale deflection when a current of $2 \ A$ passes through it. If it is to be converted into an ammeter to measure a maximum current of $10 \ A$,the required shunt is:

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