Class 12PhysicsDual Nature of Radiation and matterEinstein's Photoelectric Equation and Energy Quantum of Radiation
DifficultWhat is zero-point energy or Fermi energy?
(N/A) Zero-point energy is the lowest possible energy that a quantum mechanical physical system may have. Unlike in classical mechanics,quantum systems fluctuate even in their ground state. For a gas of fermions,the energy of the highest occupied state at absolute zero temperature $(0 \ K)$ is called the Fermi energy $(E_F)$.
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$A$ photon of wavelength $3315 \ \text{Å}$ falls on a photocathode and an electron of energy $3 \times 10^{-19} \ \text{J}$ is ejected. The threshold wavelength of the photon is [Planck's constant $(h)$ $= 6.63 \times 10^{-34} \ \text{J-s}$, velocity of light $(c)$ $= 3 \times 10^{8} \ \text{m/s}$]. (in $\text{Å}$)
$A$ metal surface is illuminated by light of a given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one-fourth of its original value, then the maximum kinetic energy of the emitted photoelectrons would become
Explain Einstein's photoelectric effect and derive Einstein's photoelectric equation.
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View SolutionFor photoelectric emission from a certain metal,the cutoff frequency is $\nu$. If radiation of frequency $2\nu$ impinges on the metal plate,the maximum possible velocity of the emitted electron will be ($m$ is the electron mass).
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View SolutionThe magnetic field associated with a light wave is given,at the origin,by $B = B_0 [\sin(3.14 \times 10^7 ct) + \sin(6.28 \times 10^7 ct)]$. If this light falls on a silver plate having a work function of $4.7 \ eV$,what will be the maximum kinetic energy of the photoelectrons? (in $eV$)
DifficultJEE MAIN 2019
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