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(A) Let the value in place of the question mark be $x$.Then the equation becomes $\frac{x}{\sqrt{128}} = \frac{\sqrt{162}}{x}$.By cross-multiplying,we

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$12$

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(A) Let the value in place of the question mark be $x$.Then the equation becomes $\frac{x}{\sqrt{128}} = \frac{\sqrt{162}}{x}$.By cross-multiplying,we get $x^2 = \sqrt{128} 	imes \sqrt{162}$.$x^2 = \sqrt{128 	imes 162}$.$x^2 = \sqrt{(64 	imes 2) 	imes (81 	imes 2)}$.$x^2 = \sqrt{64 	imes 81 	imes 4}$.$x^2 = 8 	imes 9 	imes 2$.$x^2 = 144$.$x = \sqrt{144} = 12$.

What should come in place of both the question marks in the equation $\frac{?}{\sqrt{128}} = \frac{\sqrt{162}}{?}$?

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