What will be $X$ and $Y$ in the following reactions?

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(A) $(i)$ Toluene on oxidation with $KMnO_4/KOH$ gives benzoic acid $(X)$,which on bromination gives $m$-bromobenzoic acid $(Y)$.
$(ii)$ $CH_3CHO$ with Tollen's reagent gives ethanoic acid $(X)$,which on reduction with $LiAlH_4$ gives ethanol $(Y)$.
$(iii)$ $o$-xylene $(X)$ on oxidation gives phthalic acid $(Y)$.
$(iv)$ Benzoic acid with $NH_3$ gives ammonium benzoate $(X)$,which on heating gives benzamide $(Y)$.
$(v)$ Phthalic acid with $NH_3$ gives ammonium phthalate $(X)$,which on heating gives phthalamide $(Y)$.

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The product $(A)$ of the reaction is:

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In the given reaction,$[X]$ will be:

In Column - $I$ the structure of the compound is given,in Column - $II$ the boiling point,and in Column - $III$ the functional group is given. Find the correct match for Column - $I$ from Column - $II$ and Column - $III$.
Column - $I$ (Formula)Column - $II$ (Boiling Point)Column - $III$ (Group)
$(A)$ $CH_3COOH$$(i)$ $309 \ K$$(m)$ Alkane
$(B)$ $CH_3CH_2CH_2OH$$(ii)$ $322 \ K$$(n)$ Ketone
$(C)$ $CH_3COCH_3$$(iii)$ $329 \ K$$(o)$ Aldehyde
$(D)$ $CH_3CH_2CHO$$(iv)$ $391 \ K$$(p)$ Carboxylic acid
$(E)$ $CH_3CH_2CH_2CH_2CH_3$$(v)$ $370 \ K$$(q)$ Alcohol

Match the compounds given in Column-$I$ with their names in Column-$II$.
Column-$I$ (Formula)Column-$II$ (Name)
$(A)$ $CH_3-CH=CHCHO$$(i)$ $1,3$-diphenylprop-$2$-en-$1$-one
$(B)$ $CH_3-C(CH_3)=CH-COCH_3$(ii) Acetophenone-$2,4$-dinitrophenylhydrazone
$(C)$ $C_6H_5-CH=CH-COC_6H_5$(iii) But-$2$-enal
$(D)$ $C_6H_5-C(CH_3)=N-NH-C_6H_3(NO_2)_2$(iv) $4$-methylpent-$3$-en-$2$-one

The product $(A)$ of the reaction is:

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