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(C) The number of moles $n$ is given by $n = \frac{m}{M} = \frac{N}{N_A}$, where $m$ is the mass, $M$ is the molar mass, $N$ is the number of atoms, a

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$8.0 	imes 10^7 	ext{ J}$

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(C) The number of moles $n$ is given by $n = \frac{m}{M} = \frac{N}{N_A}$, where $m$ is the mass, $M$ is the molar mass, $N$ is the number of atoms, and $N_A$ is Avogadro's number.Given $m = 1 	ext{ mg} = 10^{-3} 	ext{ g}$, $M = 240 	ext{ g/mol}$, and $N_A = 6 	imes 10^{23} 	ext{ atoms/mol}$.The number of atoms $N$ is:$N = \frac{m}{M} 	imes N_A = \frac{10^{-3}}{240} 	imes 6 	imes 10^{23} = 2.5 	imes 10^{18} 	ext{ atoms}$.The energy released per fission is $E_f = 200 	ext{ MeV} = 200 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 3.2 	imes 10^{-11} 	ext{ J}$.Total energy released $E = N 	imes E_f = 2.5 	imes 10^{18} 	imes 3.2 	imes 10^{-11} 	ext{ J} = 8.0 	imes 10^7 	ext{ J}$.

What will be the energy released in joule, in the process of fission by $1 \text{ mg}$ of ${ }_{92}^{240} U$? Assume energy release per fission is $200 \text{ MeV}$. [Use Avogadro's number as $6 \times 10^{23}$ and $1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$]

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