When a 4 ,kg rifle is fired,the 10 ,g bullet | vedclass

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(C) According to Newton's third law of motion,for every action,there is an equal and opposite reaction. The force exerted by the rifle on the bullet i

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$300$

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(C) According to Newton's third law of motion,for every action,there is an equal and opposite reaction. The force exerted by the rifle on the bullet is equal in magnitude to the force exerted by the bullet on the rifle.First,convert the given values into $SI$ units:Mass of the bullet,$m = 10 \,g = 0.01 \,kg$.Acceleration of the bullet,$a = 3 	imes 10^6 \,cm/s^2 = 3 	imes 10^6 	imes 10^{-2} \,m/s^2 = 3 	imes 10^4 \,m/s^2$.The force acting on the bullet is $F = m 	imes a$.$F = 0.01 \,kg 	imes 3 	imes 10^4 \,m/s^2 = 300 \,N$.Since the force acting on the rifle is equal in magnitude to the force acting on the bullet,the magnitude of the force acting on the rifle is $300 \,N$.

When a $4 \,kg$ rifle is fired,the $10 \,g$ bullet receives an acceleration of $3 \times 10^6 \,cm/s^2$. The magnitude of the force acting on the rifle (in newton) is ............

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