When a cell of $E.M.F.$ $E_1$ is connected to a potentiometer wire,the balancing length is $l_1$. Another cell of $E.M.F.$ $E_2$ $(E_1 > E_2)$ is connected such that the two cells oppose each other,then the balancing length is $l_2$. The ratio $E_1 : E_2$ is

  • A
    $\frac{l_1}{l_1+l_2}$
  • B
    $\frac{l_1+l_1-l_2}{l_1-l_2}$
  • C
    $\frac{l_1+l_2}{l_1}$
  • D
    $\frac{l_1+l_2}{l_1-l_2}$

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