When a metallic surface is illuminated with monochromatic light of wavelength $\lambda$,the stopping potential is $5V_0$. When the same surface is illuminated with light of wavelength $3\lambda$,the stopping potential is $V_0$. Then the work function of the metallic surface is:

  • A
    $\frac{hc}{6\lambda}$
  • B
    $\frac{hc}{5\lambda}$
  • C
    $\frac{hc}{4\lambda}$
  • D
    $\frac{2hc}{4\lambda}$

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