When conc. H_2SO_4 comes in contact with suga | vedclass

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(D) The sugar,a carbohydrate such as $C_{12}H_{22}O_{11}$,is mixed with concentrated sulfuric acid,$H_2SO_4$. The sulfuric acid acts as a strong dehyd

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Dehydration

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(D) The sugar,a carbohydrate such as $C_{12}H_{22}O_{11}$,is mixed with concentrated sulfuric acid,$H_2SO_4$. The sulfuric acid acts as a strong dehydrating agent and removes water molecules from the carbohydrate,leaving behind elemental carbon. The reaction is: $C_{12}H_{22}O_{11} \xrightarrow{H_2SO_4} 12C + 11H_2O$. This process turns the sugar black due to the formation of carbon.

List-$I$ (Hydrides)	List-$II$ (Nature)
$a. MgH_2$	$i. \text{Electron precise}$
$b. GeH_4$	$ii. \text{Electron deficient}$
$c. B_2H_6$	$iii. \text{Electron rich}$
$d. HF$	$iv. \text{Ionic}$

When conc. $H_2SO_4$ comes in contact with sugar,it becomes black due to

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Match List-$I$ with List-$II$.

List-$I$ (Hydrides) List-$II$ (Nature)

$a. MgH_2$ $i. \text{Electron precise}$

$b. GeH_4$ $ii. \text{Electron deficient}$

$c. B_2H_6$ $iii. \text{Electron rich}$

$d. HF$ $iv. \text{Ionic}$

Choose the correct answer from the options given below:

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