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Question

(A) The given quadratic equation is $9x^{2} + \frac{3}{4}x - \sqrt{2} = 0$.To complete the square,we first express the equation in the form $(ax)^{2}

Vedclass · Accepted Answer

$\frac{1}{64}$

Vedclass · Answer

(A) The given quadratic equation is $9x^{2} + \frac{3}{4}x - \sqrt{2} = 0$.To complete the square,we first express the equation in the form $(ax)^{2} + 2(ax)(b) + b^{2}$.We can rewrite the equation as $(3x)^{2} + 2(3x)(\frac{1}{8}) - \sqrt{2} = 0$.Here,the term $b$ is $\frac{1}{8}$.To complete the square,we need to add and subtract $b^{2} = (\frac{1}{8})^{2} = \frac{1}{64}$.Thus,the constant that must be added and subtracted is $\frac{1}{64}$.

Which constant must be added and subtracted to solve the quadratic equation $9x^{2} + \frac{3}{4}x - \sqrt{2} = 0$ by the method of completing the square?

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