Difficult
Which is a wrong statement?
- AIn $\ln k$ vs $\frac{1}{T}$ plot is a straight line
- BPresence of catalyst will not alter the value of $E_a$
- CRate constant $k = $ Arrhenius constant $A$: if $E_a = 0$
- D$e^{-E_a / RT}$ gives the fraction of reactant molecules that are activated at the given temp
Explore More
Similar Questions
The time required for $10 \%$ completion of a first order reaction at $298 \,K$ is equal to that required for its $25 \%$ completion at $308 \,K$. If the value of $A$ is $4 \times 10^{10} \,s^{-1}$,calculate $k$ at $318 \,K$ and $E_a$.
Difficult
View SolutionExplain: How is the value of activation energy determined based on the Arrhenius equation?
Difficult
View SolutionThe temperature dependence of the rate constant $k$ is expressed as $k = A e^{-E_a / RT}$. When a plot between $\log k$ and $1/T$ is plotted,we get the graph as shown. What is the value of the slope in the graph?
Medium
View SolutionFor an endothermic reaction,the energy of activation is $E_a$ and the enthalpy of reaction is $\Delta H$ (both in $kJ/mol$). The minimum value of $E_a$ will be:
MediumAIPMT 2010
View SolutionFor a reaction $A \rightarrow B$,the enthalpy of reaction is $-4.2 \ kJ \ mol^{-1}$ and the enthalpy of activation is $9.6 \ kJ \ mol^{-1}$. The correct potential energy profile for the reaction is shown in which option?
MediumNEET 2021
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo