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(C) To find the number of unpaired electrons,we write the electronic configuration for each ion:$1$. $Fe^{2+}$ $(Z=26)$: $[Ar] 3d^6$. In $3d^6$,there

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$Mn^{2+}$

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(C) To find the number of unpaired electrons,we write the electronic configuration for each ion:$1$. $Fe^{2+}$ $(Z=26)$: $[Ar] 3d^6$. In $3d^6$,there are $4$ unpaired electrons.$2$. $Co^{2+}$ $(Z=27)$: $[Ar] 3d^7$. In $3d^7$,there are $3$ unpaired electrons.$3$. $Mn^{2+}$ $(Z=25)$: $[Ar] 3d^5$. In $3d^5$,there are $5$ unpaired electrons.$4$. $Cr^{2+}$ $(Z=24)$: $[Ar] 3d^4$. In $3d^4$,there are $4$ unpaired electrons.Comparing the number of unpaired electrons: $Mn^{2+}$ has the maximum number of unpaired electrons,which is $5$.

Which of the following has the maximum number of unpaired electrons?
(Atomic numbers: $Fe=26, Co=27, Mn=25, Cr=24$)

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Which of the following has the maximum number of unpaired electrons?(Atomic numbers: $Fe=26, Co=27, Mn=25, Cr=24$)