While selling a flowerpot for Rs. 96,the prof | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the cost price of the flowerpot be $x$ rupees.
Given that the profit percentage is equal to the cost price,the profit percentage is $x\%$.
P

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(D) Let the cost price of the flowerpot be $x$ rupees.
Given that the profit percentage is equal to the cost price,the profit percentage is $x\%$.
Profit = $\frac{x}{100} 	imes x = \frac{x^2}{100}$.
Selling Price = Cost Price + Profit = $x + \frac{x^2}{100}$.
Given that the selling price is Rs. $96$,we have the equation: $x + \frac{x^2}{100} = 96$.
Multiplying the entire equation by $100$,we get $100x + x^2 = 9600$.
Rearranging into a standard quadratic equation: $x^2 + 100x - 9600 = 0$.
Factoring the quadratic equation: $x^2 + 160x - 60x - 9600 = 0$.
$x(x + 160) - 60(x + 160) = 0$.
$(x - 60)(x + 160) = 0$.
This gives $x = 60$ or $x = -160$.
Since the cost price cannot be negative,the cost price is Rs. $60$.

While selling a flowerpot for Rs. $96$,the profit percentage is equal to its cost price in rupees. Find the cost price of the flowerpot.

Similar Questions

The roots of $x^{2}+12x+36=0$ are ...........

Solve the following equation using the method of factorization: $(x+1)^{2} + x^{2} = 221$.

One of the solutions of the quadratic equation $(x-3)^{2}-4=0$ is ..... .

Solve the following quadratic equation using the method of 'completing the square': $2x^2 - 7x + 3 = 0$

Examine whether the following equation is quadratic or not: $\frac{x-2}{x+2} - \frac{x+2}{x-2} = \frac{3}{7}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module