White phosphorus reacts with thionyl chloride | vedclass

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Question

(A) The chemical reaction between white phosphorus $(P_4)$ and thionyl chloride $(SOCl_2)$ is given by the following balanced equation:$P_4 + 8SOCl_2

Vedclass · Accepted Answer

$SO_2, S_2Cl_2$

Vedclass · Answer

(A) The chemical reaction between white phosphorus $(P_4)$ and thionyl chloride $(SOCl_2)$ is given by the following balanced equation:$P_4 + 8SOCl_2 \rightarrow 4PCl_3 + 4SO_2 + 2S_2Cl_2$In this reaction,$P_4$ reacts with $SOCl_2$ to produce phosphorus trichloride $(PCl_3)$,sulfur dioxide $(SO_2)$,and disulfur dichloride $(S_2Cl_2)$.Comparing this with the given products $A$ and $B$,we identify $A$ as $SO_2$ and $B$ as $S_2Cl_2$.Therefore,the correct option is $A$.

White phosphorus reacts with thionyl chloride to form $PCl_3$ along with $A$ and $B$. $A$ and $B$ respectively are

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