Why is aniline soluble in aqueous $HCl$?
(N/A) Aniline is a base that reacts with the acid $HCl$ to form a salt called anilinium chloride $(C_6H_5NH_3^+Cl^-)$.
This salt is an ionic compound,which makes it highly soluble in water.
The reaction is:
$C_6H_5NH_2 + HCl_{(aq)} \rightarrow C_6H_5NH_3^+Cl^-_{(aq)}$
This salt is an ionic compound,which makes it highly soluble in water.
The reaction is:
$C_6H_5NH_2 + HCl_{(aq)} \rightarrow C_6H_5NH_3^+Cl^-_{(aq)}$
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