Why is benzene extraordinarily stable though it contains three double bonds?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Benzene is a hybrid of resonating structures. All six carbon atoms in benzene are $sp^2$ hybridized.
The two $sp^2$ hybrid orbitals of each carbon atom overlap with the $sp^2$ hybrid orbitals of adjacent carbon atoms to form six sigma bonds in the hexagonal plane.
The remaining $sp^2$ hybrid orbital on each carbon atom overlaps with the $s$-orbital of hydrogen to form six sigma $C-H$ bonds.
The remaining unhybridized $p$-orbital of carbon atoms has the possibility of forming three $\pi$ bonds by the lateral overlap of $C_1-C_2, C_3-C_4, C_5-C_6$ or $C_2-C_3, C_4-C_5, C_6-C_1$.
The six $\pi$ electrons are delocalized and can move freely about the six carbon nuclei.
Even with the presence of three double bonds,these delocalized $\pi$-electrons provide extra stability to benzene due to resonance energy.

Explore More

Similar Questions

The stability order of the following resonance structures is:
$I. CH_2=CH-CH=O$
$II. CH_2^+-CH=CH-O^-$
$III. CH_2^--CH=CH-O^+$

$CH_3-C(=O)-OCH_3$. In the given structure,the bond between carbonyl carbon and oxygen is $a$ and the bond between oxygen and methyl group is $b$. The correct relation between the bond lengths $a$ and $b$ is:

The relative stability of the contributing structures is:

Which of the following orders of resonance energy is correct?

Write the resonance structures of $CO_3^{2-}$ and $HCO_3^{-}$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo