In a single-slit diffraction experiment,what | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The width of the central maximum in a single-slit diffraction pattern is given by $w = \frac{2D\lambda}{b}$,where $D$ is the distance to the scree

Vedclass · Accepted Answer

$0.2$

Vedclass · Answer

(C) The width of the central maximum in a single-slit diffraction pattern is given by $w = \frac{2D\lambda}{b}$,where $D$ is the distance to the screen,$\lambda$ is the wavelength,and $b$ is the slit width.The fringe width of a double-slit interference pattern is given by $\beta = \frac{D\lambda}{d}$,where $d$ is the slit separation.It is given that $20$ maxima of the double-slit pattern lie within the central maximum of the diffraction pattern. The total width occupied by $20$ interference fringes is $20 	imes \beta = 20 \frac{D\lambda}{d}$.Equating the two widths: $20 \frac{D\lambda}{d} = \frac{2D\lambda}{b}$.Simplifying the equation: $\frac{20}{d} = \frac{2}{b}$.Rearranging for $b$: $b = \frac{2d}{20} = \frac{d}{10}$.Given $d = 2 \, mm$,we get $b = \frac{2 \, mm}{10} = 0.2 \, mm$.

In a single-slit diffraction experiment,what is the width of the slit $(b)$ such that $20$ maxima of a double-slit interference pattern are obtained within the central maximum of the diffraction pattern? (Given: Slit separation for the double-slit arrangement $d = 2 \, mm$)

Similar Questions

The first diffraction minima due to a single slit diffraction is at $\theta = 30^o$ for a light of wavelength $5000 \,\mathring{A}$. The width of the slit is

Describe the simplest experiments to observe a diffraction pattern.

$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

In a single slit diffraction experiment,the width of the slit is doubled. Which one of the following statements is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module