Using the remainder theorem,find the remainde | vedclass

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(D) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ a

Vedclass · Accepted Answer

$120$

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(D) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ and the divisor is $x - 6$,so $a = 6$.Now,substitute $x = 6$ into the polynomial:$p(6) = (6)^{3} + (6)^{2} - 26(6) + 24$$p(6) = 216 + 36 - 156 + 24$$p(6) = 252 - 156 + 24$$p(6) = 96 + 24$$p(6) = 120$Therefore,the remainder is $120$.

Using the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x - 6$.

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